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**Sag and Tension:**

**Sag**is an interesting topic to discuss.We generally see a lot of overhead lines on our way.Sag in general words can be said that distance between the highest point of electric poles or towers and the lowest point of a conductor connected between two poles or towers.You will know

**how to calculate sag**and

**sag formula**.

While erecting an overhead line, it is very important that conductors are under safe

**tension**.If the conductors are too much stretched between supports in a bid to save conductor material, the stress in the conductor may reach unsafe value and in certain cases, the conductor may break due to excessive tension.In order to permit safe

**tension**in the conductors, they are not fully stretched but are allowed to have a dip or

**sag**.

The difference in level between points of supports and the lowest point on the conductor is called.sag

**Must Read:**

Figure (i) below shows a conductor suspended between two equilevel supports A and B.The conductor is not fully stretched but is allowed to have a dip.The lowest point on the conductor is O and the sag is S.The following points may be noted :

(i) When the conductor is suspended between two supports at the same level, it takes the shape of a catenary.However, if the

**sag**is very small compared with the span, then the

**sag span curve**is like a parabola.

(ii) The tension at any point on the conductor acts tangentially.Thus tension TO at the lowest point O acts horizontally as shown in Figure (ii).

(iii) The horizontal component of tension is constant throughout the length of the wire.

(iv) The

**tension**at supports is approximately equal to the horizontal tension acting at any point on the wire.Thus if T is the tension at the support B, then T = TO.

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**Conductor sag & tension:**

This is an important consideration in the **mechanical design of**

**overhead lines**.The conductor

**sag**should be kept to a minimum in order to reduce the conductor material required and to avoid extra pole height for sufficient clearance above ground level.It is also desirable that tension in the conductor should be low to avoid the mechanical failure of conductor and to permit the use of less strong supports.However, low

**conductor tension**and

**minimum sag**are not possible.It is because low sag means a tight wire and high tension, whereas a low tension means a loose wire and increased sag.Therefore, in actual practice, a compromise is made between the two.

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**Calculation of Sag in Overhead transmission lines:**

In an **overhead line**, the

*sag*should be so adjusted that tension in the conductors is within safe limits.The tension is governed by conductor weight, effects of the wind, ice loading and temperature variations.It is a standard practice to keep conductor tension less than 50% of its ultimate tensile strength i.e., minimum factor of safety in respect of

**conductor tension**should be 2.We shall now calculate

**sag and**

**tension**of a conductor when

(i) supports are at equal levels

(ii) supports are at unequal levels

(i) When supports are at equal levels: Consider a conductor between two equilevel supports A and B with O as the lowest point as shown in the figure below.It can be proved that lowest point will be at the mid-span.Let

l = Length of span

w = Weight per unit length of conductor

T =

**Tension**in the conductor.

Consider a point P on the conductor.Taking the lowest point O as the origin, let the coordinates of point P be x and y.Assuming that the curvature is so small that curved length is equal to its horizontal projection (i.e., OP = x), the two forces acting on the portion OP of the conductor are :

(a) The weight wx of conductor acting at a distance x/2 from O.

(b) The tension T acting at O.

Equating the moments of above two forces about point O, we get,

The maximum dip (

**sag**) is represented by the value of y at either of the supports A and B.At support A, x = l/2 and y = S.

**(ii) When supports are at unequal levels:**In hilly areas, we generally come across conductors suspended between supports at unequal levels.The figure below shows a conductor suspended between two supports A and B which are at different levels.The lowest point on the conductor is O.

Let l = Span length

h = Difference in levels between two supports

x1 = Distance of support at lower level (i.e., A) from O

x2 = Distance of support at higher level (i.e. B) from O

T =

**Tension**in the conductor

If w is the weight per unit length of the conductor, then,

Also x1 + x2 = l

Having found x1 and x2 , values of S1 and S2 can be easily calculated.

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**Effect of wind & ice loading on ****electrical transmission lines**** :**

The above **formula for sag**are true only in still air and at normal temperature when the conductor is acted by its weight only.However, in actual practice, a conductor may have ice coating and simultaneously subjected to wind pressure.The weight of ice acts vertically downwards i.e., in the same direction as the weight of conductor.The force due to the wind is assumed to act horizontally i.e., at the right angle to the projected surface of the conductor.Hence, the total force on the conductor is the vector sum of horizontal and vertical forces as shown in Figure(iii) below.

Total weight of conductor per unit length is

When the conductor has the wind and ice loading also, the following points may be noted :

(i) The conductor sets itself in a plane at an angle θ to the vertical where

(ii) The

**sag in the conductor**is given by :

Hence S represents the slant

**sag**in a direction making an angle θ to the vertical.If no specific mention is made in the problem, then slant slag is calculated by using the above formula.

(iii) The vertical sag = S cos θ

**Conclusion:**

You have learnt

**What is Sag & Tension in transmission lines**&

**how to Calculate it**and

**sag formula**.If you have any queries mail us @

**[email protected]**